The perimeter of a rectangle is 72. the length of the rectangle is twice the width. Find the dimensions of the rectangle.
2(w + 2w) = 72
Perimeter is 72..length is 12 and width is 6
To find the dimensions of the rectangle, we can set up an equation based on the given information.
Let's assume the width of the rectangle is 'w'.
According to the problem, the length of the rectangle is twice the width, so the length would be '2w'.
The perimeter of a rectangle is calculated by adding the lengths of all its sides. In this case, it can be calculated as:
Perimeter = 2(Length + Width)
Substituting the given values into the equation, we get:
72 = 2(2w + w)
Now, let's solve this equation to find the value of 'w'.
First, simplify the equation:
72 = 2(3w)
Divide both sides of the equation by 2:
36 = 3w
Next, isolate 'w' by dividing both sides of the equation by 3:
w = 12
Now that we have the value of 'w' (width), we can find the value of the length:
Length = 2w
Length = 2(12)
Length = 24
Therefore, the dimensions of the rectangle are width = 12 and length = 24.