calculate the energy required to raise the temp of 72g of water from 50c tp 150

What do you not understand about this? Anytime you are within a phase it is

q = mass x specific heat x (Tfinal-Tinitial)
Phase changaes are different.
At the melting point it is q = mass x heat fusion.
At the boiling point it is q = mass x heat vaporization.

Those three equation will solve all of the problems with heating a substance.

To calculate the energy required to raise the temperature of a substance, you can use the equation:

Q = m * c * ΔT

where:
- Q is the energy required (in joules),
- m is the mass of the substance (in grams),
- c is the specific heat capacity of the substance (in joules per gram degree Celsius),
- ΔT is the change in temperature (in degrees Celsius).

In this case, we are dealing with water, which has a specific heat capacity of 4.18 J/g°C.

First, let's calculate the change in temperature (ΔT):
ΔT = final temperature - initial temperature
ΔT = 150°C - 50°C
ΔT = 100°C

Now, we can substitute the values into the equation:
Q = 72g * 4.18 J/g°C * 100°C

Calculating the energy required:
Q = 301,536 J

Therefore, the energy required to raise the temperature of 72g of water from 50°C to 150°C is 301,536 joules.