How many milliliters of 3.6 M HCl must be transfered from a reagent bottle to provide 20 g HCl for a reaction?
Answer in units of mL
How many moles in 20 g HCl? That is 20/molar mass HCl = ?? moles
M HCl = moles HCl/L HCl.
You know moles and M, solve for L and convert to mL.
To find the number of milliliters (mL) of 3.6 M HCl needed to provide 20 g of HCl, we can use the equation:
Moles = mass / molar mass
First, we need to calculate the moles of HCl required. The molar mass of HCl is approximately 36.46 g/mol (which is the sum of the atomic masses of hydrogen and chlorine).
Moles of HCl = 20 g / 36.46 g/mol
Next, we can use the molarity (M) of the HCl solution to relate moles to volume using the equation:
Moles = Molarity x Volume
We rearrange the equation to solve for the volume:
Volume (in liters) = Moles / Molarity
Since the molarity (M) is given as 3.6 M and we want the answer in mL, we need to convert the volume from liters to milliliters.
1 L = 1000 mL
Let's calculate the volume:
Volume (in liters) = (20 g / 36.46 g/mol) / 3.6 M
Volume (in liters) = 0.5487 mol / 3.6 M
Volume (in liters) ≈ 0.1524 L
Now, let's convert the volume from liters to milliliters:
Volume (in mL) = 0.1524 L x 1000 mL/L
Volume (in mL) ≈ 152 mL
Therefore, approximately 152 mL of 3.6 M HCl must be transferred from the reagent bottle to provide 20 g HCl for the reaction.