physics

A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead the pipe's diameter is 56.3 cm (0.563 m) and the flow speed of the petroleum is 13.5 m/s. At the refinery the petroleum flows at 5.65 m/s. What is the volume flow rate of the petroleum along the pipe and what is the pipe\'s diameter at the refinery?

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  1. flow rate = Q = pi r^2 v
    = amount per second that flows through the pipe
    so
    Q = pi (.563)^2 (13.5)

    if no oil has been added or subtracted or compressed then Q is the same everywhere
    so

    pi (D^2/4) (5.65) = Q

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