A stunt man 60kg jumps down straight down at bozs below 10m from a balcony and he's going down at a speed of 50km/h. What is the force exerted on the boxs?
To calculate the force exerted on the boxes, we need to use the formula for force: force = mass × acceleration.
First, let's convert the speed of the stuntman from km/h to m/s. We multiply 50 km/h by 1000 m/km and divide by 3600 s/h to get the speed in m/s.
50 km/h × 1000 m/km ÷ 3600 s/h = 13.9 m/s (rounded to one decimal place).
Next, we need to calculate the acceleration of the stuntman. We can use the equation vf² = vi² + 2as, where vf is the final velocity (0 m/s since the stuntman eventually comes to a stop), vi is the initial velocity (13.9 m/s), a is the acceleration, and s is the distance traveled (10 m).
0 m/s = (13.9 m/s)² + 2a × 10 m.
Rearranging the equation, we get:
(13.9 m/s)² = -2a × 10 m.
Simplifying further:
193.21 m²/s² = -20a.
Now, solve for acceleration:
a = 193.21 m²/s² ÷ -20 = -9.66 m/s² (rounded to two decimal places).
Since we know the mass of the stuntman is 60 kg, we can calculate the force exerted on the boxes:
force = mass × acceleration = 60 kg × -9.66 m/s² = -579.6 N (rounded to one decimal place).
Therefore, the force exerted on the boxes is approximately -579.6 N. The negative sign indicates that the force is in the opposite direction to the motion of the stuntman.