A student drops a stopper into 50.0mL of water and the level rises to to 56.1mL. If she submerges the same stopper into a cylinder of thick syrup, what will happen to the syrup?
a.) it will rise 6.1mL
b.) it will rise less than 6.1mL
c.) it will rise greater than 6.1mL
d.) it's impossible to say without knowing the density of the syrup
Please explain why thank you very much :)
i had the same question and someone said a but i do not know why still
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To answer this question, we need to understand the concept of buoyancy and the relationship between the volume of an object and the liquid it displaces. The buoyant force is the force exerted by a fluid on an immersed object. It opposes the weight of the object and depends on the density of the fluid.
When the student drops the stopper into the water, it displaces some of the water, causing the water level to rise. The water level rises by 6.1 mL, which is equal to the volume of the stopper. This shows that the volume of the stopper and the volume of water displaced are equal.
If the student now submerges the same stopper into a cylinder of thick syrup, we can predict what will happen based on our understanding of buoyancy. The buoyant force exerted by the syrup on the stopper will be equal to the weight of the stopper.
Since we do not have any additional information about the density or weight of the stopper or the density of the syrup, it is impossible to say for certain what will happen to the syrup. We need the density of the syrup to calculate the buoyant force, and without knowing that, we cannot determine how much the syrup will rise.
Hence, the correct answer is:
d.) It's impossible to say without knowing the density of the syrup.