A golf ball rolled off the edge of a table that has a height of 1.25 m and lands 0.48 m away from the table. The golf ball took 0.505 s to hit the ground 0.48 m from the table. What was the horizontal velocity, to the nearest hundredth m/s, of the ball as it rolled off the table?

Question

A golf ball rolled off the edge of a table that has a height of 1.25 m and lands 0.48 m away from the table. The golf ball took 0.505 s to hit the ground 0.48 m from the table. What was the horizontal velocity, to the nearest hundredth m/s, of the ball as it rolled off the table?

Answer 1

distance=velocity*time

.48m=v*.505s
solve for v

Answer 2

I have a follow-up question. So the horizontal velocity that we solved or, is that considered the initial or final velocity?

Answer 3

To find the horizontal velocity of the ball as it rolled off the table, we can use the equation:

horizontal velocity = horizontal displacement / time

In this case, the horizontal displacement is given as 0.48 m, and the time is given as 0.505 s.

So, to find the horizontal velocity, we can calculate:

horizontal velocity = 0.48 m / 0.505 s

Using a calculator, the result is approximately 0.9515 m/s.

Therefore, to the nearest hundredth m/s, the horizontal velocity of the ball as it rolled off the table is 0.95 m/s.