Two cars,A and B, are traveling in the sam direction, although car A is 208m behind car B. The speed of A is 24.4 m/s, and the speed of B ia 18.6m/s. How much time does it take for A to catch B?
The answer is 208/5.8 which equals 35.8 seconds.
Since displacement is equal to change in velocity times time (d = v*t) -- rearranging the equation to solve for time you get time is equal to change in distance divided by change in velocity -- or t = 208/5.8
To solve this problem, you need to use the formula for time, which is time = distance / speed.
First, let's find the relative speed between car A and car B. Since they are traveling in the same direction, you need to subtract their speeds to get the relative speed.
Relative speed = speed of A - speed of B
= 24.4 m/s - 18.6 m/s
= 5.8 m/s
Now, you can use the formula for time to find how long it takes for car A to catch up to car B.
Time = distance / relative speed
= 208 m / 5.8 m/s
= 35.8 seconds
So, it takes 35.8 seconds for car A to catch up to car B.