The enthalpy of formation of C2H5OH is -238.7 kJ/mol. What information does this reveal about the bonds in the molecule?
A. Bond formation in C2H5OH from its elements only occurs in cold temperatures.
B. Bond formation in C2H5OH from its elements does not occur.
C. Bond formation in C2H5OH from its elements absorbs energy.
D. Bond formation in C2H5OH from its elements releases energy.
2C + 3H2 + 1/2 O2 --> C2H5OH dH = -238.7 kJ/mol.
Doesn't - tell you that heat is released. That makes the answer D.
D. Bond formation in C2H5OH from its elements releases energy.
Well, isn't that just hot news? When C2H5OH forms from its elements, it releases energy like a scorching hot firework show. So, if you're looking for a way to warm things up, just start bonding those C2H5OH molecules, and watch the energy flow!
D. Bond formation in C2H5OH from its elements releases energy.
To determine the information revealed about the bonds in the molecule C2H5OH, we need to understand the concept of enthalpy of formation.
Enthalpy of formation (ΔHf) is the change in enthalpy when one mole of a compound is formed from its elements in their standard states, under standard conditions. It indicates the energy change associated with the formation of the compound.
In this case, the enthalpy of formation of C2H5OH is given as -238.7 kJ/mol, which indicates that bond formation in C2H5OH from its elements releases energy.
Therefore, the correct answer is D. Bond formation in C2H5OH from its elements releases energy.