The Pike basketball team held a raffle to earn money for a trip to an out of state basketball tournament. Tickest for the raffle were sold for either $5 or $2. The team sold a total of 500 tickets for a total of $1,450. How many $5 tickets and $2 tickets did the team sell
$5=F
$2=T
F+T=500
5F+2T=$1450
solve for either variable on either equation and plug into equation you did not use.
the rest should pretty straightforward from there
Vtge tgbtr
To solve this problem, we can set up a system of equations. Let's call the number of $5 tickets x and the number of $2 tickets y.
We know that the team sold a total of 500 tickets, so we can write the equation:
x + y = 500 ...(1)
We also know that the total amount earned from selling the tickets was $1,450. Since each $5 ticket sold for $5 and each $2 ticket sold for $2, we can write another equation:
5x + 2y = 1450 ...(2)
Now we have a system of equations with two variables. We can solve this system to find the values of x and y.
We can start by multiplying both sides of equation (1) by 2 to get rid of the y coefficient:
2x + 2y = 1000 ...(3)
Now we can subtract equation (3) from equation (2) to eliminate the y variable:
(5x + 2y) - (2x + 2y) = 1450 - 1000
3x = 450
Dividing both sides of the equation by 3, we get:
x = 150
Now we can substitute the value of x into equation (1) to solve for y:
150 + y = 500
y = 500 - 150
y = 350
Therefore, the team sold 150 $5 tickets and 350 $2 tickets.