math

the perimeter of a rectangle is 56 m. the width of the rectangle is 4 m less than the length. find the length and width of the rectangle

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asked by ulol
  1. W = L - 4


    P = 2 W + 2 L

    P = 2 ( W + L )

    P = 2 ( L - 4 + L )

    P = 2 ( 2 L - 4 )

    P = 2 * 2 L - 2 * 4

    P = 4 L - 8

    56 = 4 L - 8 Add 8 to both sides

    56 + 8 = 4 L - 8 + 8

    64 = 4 L Divide both sides by 4

    64 / 4 = 4 L / 4

    16 = L

    L = 16 m


    W = L - 4 = 16 - 4 = 12 m


    Proof:

    P = 2 ( W + L ) = 2 * ( 12 + 16 ) = 2 * 28 = 56 m

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    posted by Bosnian

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