# math

the perimeter of a rectangle is 56 m. the width of the rectangle is 4 m less than the length. find the length and width of the rectangle

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3. 9
1. W = L - 4

P = 2 W + 2 L

P = 2 ( W + L )

P = 2 ( L - 4 + L )

P = 2 ( 2 L - 4 )

P = 2 * 2 L - 2 * 4

P = 4 L - 8

56 = 4 L - 8 Add 8 to both sides

56 + 8 = 4 L - 8 + 8

64 = 4 L Divide both sides by 4

64 / 4 = 4 L / 4

16 = L

L = 16 m

W = L - 4 = 16 - 4 = 12 m

Proof:

P = 2 ( W + L ) = 2 * ( 12 + 16 ) = 2 * 28 = 56 m

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posted by Bosnian

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