3x-4 to y+15
is constant and
y=3 when x=2
then when
y=12, x equals?
My answer was 13. Im not sure how to solve this question. Could you please go through the steps so I can see they match up with mines.
My Steps:
3x-y:y+15 The original problem above says 3x-4 and not 3x-y. Try it again. I have 7/3 for the answer.
3x-12:12+15
3x-12:27
-12-27:-3x
-39:-3x
13:x
I'll try again:
3x-4:y+15
3x:12+15+4
3x:31
Now what. Is what I did right?
I need help with this problem.
Given that the ratio of
3x-4 to y+15
is constant and
y=3 when x=2
then when
y=12, x equals?
My answer was 13. Im not sure how to solve this question. Could you please go through the steps so I can see they match up with mines.
My Steps:
3x-y:y+15
3x-12:12+15
3x-12:27
-12-27:-3x
-39:-3x
13:x
The problem said the ratio was a constant when x=2 and y=3
I substituted x = 2 and y=3 and solved for the constant.
(3x-4)/(y+15) = k
I found 1/9 for k.
Then I started anew, substituted y=12 and solved for x.
There may be an easier way to do it but I think this will work.
I tried that did I not. I honestly don't understand. Can you please type it out.
Apologies for any confusion. Let's go through the steps again to find the value of x when y = 12.
Given: (3x - 4) / (y + 15) = constant
Step 1:
Substitute the values of x = 2 and y = 3 into the equation:
(3(2) - 4) / (3 + 15) = constant
Simplify:
2 / 18 = constant
1 / 9 = constant
So, we have the value of the constant as 1/9.
Step 2:
Now, we need to find the value of x when y = 12.
Substitute y = 12 and the constant value into the equation:
(3x - 4) / (12 + 15) = 1/9
Simplify:
(3x - 4) / 27 = 1/9
To solve for x, we can cross-multiply:
9(3x - 4) = 27 * 1
Expand:
27x - 36 = 27
Add 36 to both sides:
27x = 27 + 36
27x = 63
Divide both sides by 27:
x = 63 / 27
x = 7/3
So, the value of x when y = 12 is 7/3 or approximately 2.33.
Therefore, your original answer of 13 was incorrect. The correct value for x when y = 12 in this problem is 7/3 or approximately 2.33.