Oxygen gas may be prepared by decomposing hydrogen peroxide, h2o2, using manganese (IV) oxide catalyst: 2H2O2(liquid) ----> 2H2O(liquid) + O2(gas)

Calculate the amount of oxygen that will be produced from 1.35 moles of H2O2

Determine the mass of oxygen gas that can be prepared from 2.46 g of hydrogen peroxide

To calculate the amount of oxygen produced from a given amount of hydrogen peroxide, we can use stoichiometry. The balanced equation tells us that 2 moles of hydrogen peroxide (H2O2) will produce 1 mole of oxygen gas (O2).

1. Calculate the amount of oxygen produced from 1.35 moles of H2O2:
Using the stoichiometric ratio from the balanced equation, we know that 2 moles of H2O2 produce 1 mole of O2.
1.35 moles of H2O2 * (1 mole O2 / 2 moles H2O2) = 0.675 moles of O2

Therefore, 1.35 moles of H2O2 will produce 0.675 moles of O2.

2. Determine the mass of oxygen gas produced from 2.46 g of H2O2:
To solve this, we need to convert the given mass of H2O2 (in grams) to moles and then use the stoichiometric ratio to find the moles of O2 produced. Finally, we can convert the moles of O2 to grams.

First, calculate the moles of H2O2:
Using the molar mass of H2O2 (34.0147 g/mol), we can convert grams to moles.
2.46 g H2O2 * (1 mol H2O2 / 34.0147 g H2O2) = 0.072 moles H2O2

Next, use the stoichiometric ratio to find the moles of O2 produced:
According to the balanced equation, 2 moles of H2O2 produce 1 mole of O2.
0.072 moles H2O2 * (1 mole O2 / 2 moles H2O2) = 0.036 moles O2

Finally, convert moles of O2 to grams:
Using the molar mass of O2 (31.9988 g/mol), we can convert moles to grams.
0.036 moles O2 * (31.9988 g O2 / 1 mol O2) = 1.152 g O2

Therefore, 2.46 g of H2O2 will produce 1.152 g of O2.