Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling 40 miles per hour. Train B is traveling 48 miles an hour. Train A passes a station at 10:25 pm. If train B passes the same station at 10:55 pm, at what time will train B catch up with train A ?

When will train B catch up with train A _:_ A.M. or P.M.

The distance between the trains decreases at a rate of 8 miles per hour, if they both are moving. At 10:55 pm, the distance between the trains is (1/2 hour)* 40 mph = 20 miles. The time to catch up is 20 miles/8 mph = 2.5 hours. One will pass the other at 2.5 hours after 10:55 PM

The answer is 1:30 AM

Thank You

Not 1:30 its 1:25

To find out when Train B will catch up with Train A, we need to calculate the time difference between when Train A passes the station and when Train B passes the station.

Let's first determine the time that Train B takes to catch up with Train A.

The time difference between when Train A passes the station at 10:25 pm and when Train B passes the same station at 10:55 pm is 30 minutes.

Next, we need to calculate the distance that Train A travels during this time. Since Train A is traveling at a speed of 40 miles per hour, in 30 minutes, it will cover a distance of (40 miles/hour) * (30 minutes / 60 minutes) = 20 miles.

Now, we can determine the time it will take for Train B to catch up with Train A. The relative speed of Train B with respect to Train A is 48 miles per hour - 40 miles per hour = 8 miles per hour.

To cover the 20 miles distance between Train A and Train B at a relative speed of 8 miles per hour, it will take Train B (20 miles) / (8 miles per hour) = 2.5 hours.

Adding this time to the time that Train B passes the station at 10:55 pm, we find that Train B will catch up with Train A at 10:55 pm + 2.5 hours = 1:25 am.

Therefore, Train B will catch up with Train A at 1:25 A.M.