1) Determine the force of gravitational attraction between the earth(m=5.98*10^24kg) and a 70-kg physics student if the student is in an airplane at 4.950 meters above the earth's surface.

1) Planet Zero has a mass of 5.0*10^23 kg and a radius of 2.0*10^6 meters. What is the acceleration of gravity on planet zero?

2)Phobos, a satellite of Mars, has a radius of 11km and a mass of 10^16 kg. Its a bit lumpy, but let's assume its spherical to get a doable problem.
(a) What is G on Phobos?
3)Find the force of gravity between you and your pen if the writing device has the mass of 5.6 grams...estimate the difference.

686.3 kg

To determine the force of gravitational attraction between the Earth and the physics student, we can use Newton's law of universal gravitation, which states that the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The formula for calculating the force of gravitational attraction (F) is:

F = (G * m1 * m2) / r^2

Where:
F is the force of gravitational attraction,
G is the gravitational constant (approximately 6.67430 × 10^-11 N m^2/kg^2),
m1 and m2 are the masses of the two objects, and
r is the distance between their centers of mass.

In this case, the mass of the Earth (m1) is given as 5.98 × 10^24 kg, and the mass of the student (m2) is 70 kg. The distance between the student and the center of the Earth (r) is given as 4.950 meters above the Earth's surface.

Now, we can plug these values into the formula and calculate the force:

F = (6.67430 × 10^-11 N m^2/kg^2 * 5.98 × 10^24 kg * 70 kg) / (4.950 meters + Earth's radius)^2

To get the Earth's radius, we can assume it as approximately 6,371 kilometers (6.371 × 10^6 meters).

F = (6.67430 × 10^-11 N m^2/kg^2 * 5.98 × 10^24 kg * 70 kg) / (4.950 meters + 6.371 × 10^6 meters)^2

Calculating this equation will give us the force of gravitational attraction between the Earth and the student.