What mass of carbon dioxide will be produced when 0.250 mol of propane(C3H8) reacts with 25.0 g of oxygen? Write a balanced equation first.
To write the balanced equation for the reaction between propane (C3H8) and oxygen (O2), we need to ensure that there is an equal number of atoms on both sides of the equation.
C3H8 + O2 -> CO2 + H2O
Now that we have the balanced equation, we can use stoichiometry to determine the mass of carbon dioxide (CO2) produced.
Step 1: Convert grams of oxygen (O2) to moles using its molar mass.
The molar mass of oxygen is 32.00 g/mol.
25.0 g / 32.00 g/mol = 0.78125 mol of oxygen
Step 2: Use the balanced equation to find the mole ratio between propane and carbon dioxide.
From the balanced equation, the mole ratio between propane (C3H8) and carbon dioxide (CO2) is 1:3.
This means that for every 1 mole of propane, 3 moles of carbon dioxide are produced.
Step 3: Calculate the moles of carbon dioxide produced.
Since we have 0.250 mol of propane, we can calculate the moles of carbon dioxide as follows:
0.250 mol propane x (3 mol CO2 / 1 mol propane) = 0.750 mol CO2
Step 4: Convert moles of carbon dioxide to grams using its molar mass.
The molar mass of carbon dioxide is 44.01 g/mol.
0.750 mol x 44.01 g CO2/mol = 33.01 g CO2
Therefore, 33.01 g of carbon dioxide will be produced when 0.250 mol of propane reacts with 25.0 g of oxygen.