a 33 kg lawnmower is pulled by a 100N force on flat ground. The handle makes a 10 degree angle with the ground. The coefficient of friction between grass and lawnmower wheels is 0.10.

Calculate normal force, force of friction and acceleration

To calculate the normal force, force of friction, and acceleration, we can follow these steps:

Step 1: Resolve the force applied into its vertical and horizontal components.
The vertical component of the force can be calculated as: F_vert = F * sin(angle)
The horizontal component of the force can be calculated as: F_horiz = F * cos(angle)
where F is the total applied force of 100N and angle is 10 degrees.

Step 2: Calculate the normal force.
The normal force (N) is the force exerted by the ground on the lawnmower perpendicular to the surface. It is equal in magnitude and opposite in direction to the vertical force acting on the lawnmower. So, N = F_vert.

Step 3: Calculate the force of friction.
The force of friction (F_friction) can be calculated using the formula: F_friction = coefficient of friction * N
where the coefficient of friction is given as 0.10 and N is the normal force calculated in step 2.

Step 4: Calculate the acceleration.
The equation for the net force acting on an object is given by: Net force = mass * acceleration.
Since the only horizontal force acting on the lawnmower is the force of friction, the net force can be written as: Net force = F_friction.
So, F_friction = mass * acceleration.
Rearranging the equation, we get: acceleration = F_friction / mass.

Now, let's substitute the given values and calculate each quantity:

F_vert = 100 N * sin(10°) ≈ 17.32 N
F_horiz = 100 N * cos(10°) ≈ 96.83 N

N = F_vert ≈ 17.32 N

F_friction = coefficient of friction * N
F_friction = 0.10 * 17.32 N ≈ 1.73 N

acceleration = F_friction / mass
acceleration = 1.73 N / 33 kg ≈ 0.0525 m/s²

Therefore, the normal force is approximately 17.32 N, the force of friction is approximately 1.73 N, and the acceleration is approximately 0.0525 m/s².

what does it mean when it says pulled by a 100N on flat ground?

It means there is a horizontal force of 100N applied to the mower.