The brakes of a bike (with a person) having a mass of 63 kg, reduces it's velocity from 8.5 m/s to 0 m/s in 3.0 seconds. What is the magnitude of braking force?
To calculate the magnitude of the braking force, you can use Newton's second law of motion:
F = m * a
where F is the force, m is the mass, and a is the acceleration.
First, let's calculate the acceleration:
a = (v_f - v_i) / t
where v_f is the final velocity, v_i is the initial velocity, and t is the time.
Given:
v_f = 0 m/s
v_i = 8.5 m/s
t = 3.0 s
Substituting the values, we have:
a = (0 - 8.5) / 3.0
a = -2.83 m/s²
The negative sign indicates that the acceleration is in the opposite direction to the initial motion.
Now, we can calculate the magnitude of the braking force:
F = m * a
Given:
m = 63 kg
a = -2.83 m/s²
Substituting the values, we have:
F = 63 * -2.83
F = -178.29 N
The magnitude of the braking force is 178.29 N.
To find the magnitude of the braking force, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration:
F = m*a
In this case, the acceleration is given by the change in velocity (final velocity minus initial velocity) divided by the time taken:
a = (v_f - v_i) / t
Let's calculate the acceleration first:
Acceleration (a) = (0 m/s - 8.5 m/s) / 3.0 s
= -8.5 m/s / 3.0 s
= -2.83 m/s²
The negative sign indicates that the bicycle is decelerating or slowing down.
Now we can substitute the mass and acceleration values into the formula for force:
Force (F) = mass (m) * acceleration (a)
= 63 kg * -2.83 m/s²
Calculating the product:
F = -178.29 N
Therefore, the magnitude of the braking force exerted on the bike is approximately 178.29 N.
V = Vo + a*t
V = 0
Vo = 8.5 m/s
t = 3 s.
Solve for a.(It will be negative)
F = m*a