If the original pressure of a system is 700 torr, temp 30 C and volume 100L, what will the final volume be if the pressure is increased to 750 torr and temperature to 37C
Use (P1V1/T1) - (P2V2/T2)
Remember T must be in kelvin.
To find the final volume of a gas when the pressure and temperature change, we can use the combined gas law equation:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 = original pressure
V1 = original volume
T1 = original temperature
P2 = final pressure
V2 = final volume (what we're trying to solve for)
T2 = final temperature
Given information:
P1 = 700 torr
V1 = 100 L
T1 = 30°C + 273.15 = 303.15 K (temperature must be in Kelvin, so we add 273.15)
P2 = 750 torr
T2 = 37°C + 273.15 = 310.15 K
Now we can solve for V2 using the combined gas law equation:
(700 torr * 100 L) / (303.15 K) = (750 torr * V2) / (310.15 K)
To solve for V2, we can rearrange the equation:
750 torr * V2 = (700 torr * 100 L * 310.15 K) / (303.15 K)
V2 = [(700 torr * 100 L * 310.15 K) / (303.15 K)] / (750 torr)
V2 = (21710500 torr*L*K) / (22736250 torr)
V2 ≈ 0.954 L or 0.95 L (rounded to two decimal places)
Therefore, the final volume, when the pressure is increased to 750 torr and the temperature to 37°C, will be approximately 0.95 liters.