how many milligrams of calcium is in 1.229-g of calcium carbonate?

find the atomic wt of Ca

figure the mol wt of CaCO3

So, the mass of Ca is just

wt(Ca)/wt(CaCO3) * 1.229g

.236

To determine the number of milligrams of calcium in 1.229 grams of calcium carbonate, you need to know the molar mass of calcium carbonate and the proportion of calcium in the compound.

First, calculate the molar mass of calcium carbonate (CaCO3):
- The atomic mass of calcium (Ca) is 40.08 g/mol.
- The atomic mass of carbon (C) is 12.01 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.
Therefore, the molar mass of calcium carbonate is:
(1 × 40.08 g/mol) + (1 × 12.01 g/mol) + (3 × 16.00 g/mol) = 100.09 g/mol.

Next, calculate the proportion of calcium in calcium carbonate:
- The atomic mass of calcium (Ca) is 40.08 g/mol.
- The molar mass of calcium carbonate is 100.09 g/mol.
To find the proportion, divide the molar mass of calcium by the molar mass of calcium carbonate:
(40.08 g/mol / 100.09 g/mol) × 100 = 39.99%.

Finally, calculate the number of milligrams of calcium in 1.229 grams of calcium carbonate:
- Multiply the mass of calcium carbonate (1.229 g) by the proportion of calcium (39.99%):
1.229 g × (39.99 / 100) = 0.49114 g.

To convert grams to milligrams, multiply the value by 1000:
0.49114 g × 1000 = 491.14 mg.

Therefore, there are approximately 491.14 milligrams of calcium in 1.229 grams of calcium carbonate.