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a farmer has 120 m of fencing to make two identical rectangular enclosures using an existing wall as one side of each enclosure. The dimensions of each closure are x metres and y metres as shown. Obtain and expression in terms of x only for the total area of two enclosures, and calculate the maximum value of the area. I"m really stuck please help!

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  1. assuming the x side is parallel to the wall, then

    2x+4y = 120
    The area is

    2xy = 2x(120-2x)/4 = 60x - x^2

    The maximum area is thus where x=30

    As usual with such problems, the maximum area is achieved when the fencing is divided equally among lengths and widths.

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  2. Jxksmsms

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  3. Ncjdjdn

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