When Pb-208 bombarded with Ni-64, a new element and six neutrons are produced. What isotope of the new element is produced by this reaction?
Question 17 options:
Ds-266
Ds-272
Rf-266
Rf-272
I believe it is either rf- 272 or Ds-272 because i added 208+64, but I do not know how to find out the new name.
It's difficult to write subscripts and superscripts here so here is what I do.
The first number is the subscript(the atomic number) and the next number (on the right) is the superscript (the mass number). The sum of subscripts on the left must equal the sum of subscripts on the right; the sum of superscripgs on the left must equal the sum of superscripts on the right.
Here is what the problem tells you.
82Pb208 + 28Ni64 = yXx + 6 on1
So 82 + 28 = y + 6 and y = ?. That's the atomic number; look that up on the periodic table to identify the element X with that number.
Then 208 + 64 = z + 6. z = ? That's the mass number of element X.
I don't think either of your guesses is right.
To determine the isotope of the new element produced in the reaction between Pb-208 and Ni-64, we need to calculate the atomic number and mass number of the resulting nucleus.
When Pb-208 (atomic number 82) is bombarded with Ni-64 (atomic number 28), the total atomic numbers of the two nuclei will be conserved. Therefore, the atomic number of the new element will be 82 + 28 = 110.
To calculate the mass number, we add the mass numbers of the two nuclei. Pb-208 has a mass number of 208, and Ni-64 has a mass number of 64. Therefore, the mass number of the new element will be 208 + 64 = 272.
Based on these calculations, the correct isotope of the new element produced by this reaction is Rf-272. Thus, the correct answer is Rf-272.
To determine the isotope of the new element produced by this reaction, we need to understand the process of nuclear reactions and isotopes.
In this case, we have Pb-208 bombarded with Ni-64, which results in a new element and six neutrons being produced. The sum of the proton and neutron numbers must be conserved in a nuclear reaction. Therefore, we can start by adding the proton numbers (atomic numbers) of the reactants, which are 82 for Pb-208 and 28 for Ni-64:
82 (Pb) + 28 (Ni) = 110 (unknown new element)
Next, we add the neutron numbers (mass numbers) of the reactants:
208 (Pb) + 64 (Ni) = 272 (unknown new element)
So, based on these calculations, the mass number of the new element is 272.
To find the name of the new element, we need to consult the periodic table. The new element with atomic number 110 is called Darmstadtium (Ds). Therefore, the correct isotope of the new element produced by this reaction would be Ds-272.
Hence, the correct option is Ds-272.