If a cheetah is able to accelerate at 15.0 m/s2 from a stand still, what speed will it reach after 2.50 seconds?
vf= a*t
To find the speed the cheetah will reach after 2.50 seconds, you can use the formula for acceleration:
acceleration (a) = change in velocity (Δv) / time (t)
Rearranging the formula gives us the change in velocity:
Δv = a * t
Substituting the given values:
Δv = 15.0 m/s² * 2.50 s
Δv = 37.5 m/s
Therefore, the cheetah will reach a speed of 37.5 m/s after 2.50 seconds.
To find the speed the cheetah will reach after 2.50 seconds, we can use the formula for acceleration:
\(v = u + at\)
where:
\(v\) is the final velocity,
\(u\) is the initial velocity (0 m/s as it starts from a standstill),
\(a\) is the acceleration (15.0 m/s²),
and \(t\) is the time taken (2.50 seconds).
Plugging in the values into the formula:
\(v = 0 + (15.0 \, \text{m/s}^2) \times (2.50 \, \text{s})\)
\(v = 0 + 37.5 \, \text{m/s}\)
Therefore, the cheetah will reach a speed of 37.5 m/s after 2.50 seconds.