A car drives straight off the edge of a cliff that is 47m hight. The police at the accident note that the point of impact is 122m from the base of the cliff. How fast was the car traveling when it went over the cliff.

Calculate the time in air: that is the time to fall47 m. Then, v=122/timeinair.

To find out how fast the car was traveling when it went over the cliff, we first need to calculate the time it took for the car to fall 47 meters.

We can use the formula for free fall:

h = (1/2) * g * t^2

where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time in seconds.

In this case, the height h is 47 meters. So, we can rearrange the formula to solve for time:

t^2 = (2 * h) / g

Plugging in the values, we get:

t^2 = (2 * 47) / 9.8

t^2 = 9.59

To find t, we take the square root of both sides:

t ≈ √9.59

t ≈ 3.1 seconds (rounded to one decimal place)

Now, we have the time it took for the car to fall. To calculate the car's velocity, we can use the formula:

v = d / t

where v is the velocity, d is the distance traveled, and t is the time.

In this case, the distance traveled d is 122 meters, and the time t is 3.1 seconds.

Plugging in the values, we get:

v = 122 / 3.1

v ≈ 39.4 m/s (rounded to one decimal place)

Therefore, the car was traveling at approximately 39.4 meters per second when it went over the cliff.