calculate the total mass of carbon dioxide gas produced when you burn 1000ml of gasoline
Density of heptane = 0.684g/ml
density of octane =0.703g/ml
a) Calculate the mass of carbon dioxide produced from combustion of heptane
C7H16 + O2 ------- CO2 + H2O
b)CALCULATE THE MASS OF CARBON DIOXIDE PRODUCED FROM THE COMBUSTION OF OCTANE
C8H18 + O2 ----- CO2 + H2O
1000 mL gasoline contains how much octane and how much heptane?
thats all the info we are given but
i found the mass using the formula
density= mass/volume
mass of heptane is 648 grams and mass of octane is 703 grams i just don't know what to do next
And I don't either. Your calculation obtains the grams octane IF the entire 1000 mL is octane or grams heptane iF the entire 1000 mL is heptane but it doesn't tell you the grams of each in gasoline if gasoline were a mixture of heptane and octane.
To calculate the total mass of carbon dioxide gas produced when you burn 1000ml of gasoline, we need to consider the specific type of gasoline and its combustion equation. In this case, we have two types of gasoline - heptane (C7H16) and octane (C8H18).
a) To calculate the mass of carbon dioxide produced from the combustion of heptane (C7H16), we need to balance the combustion equation and calculate the stoichiometric ratio. The balanced equation is:
C7H16 + 11O2 → 7CO2 + 8H2O
From the balanced equation, we can see that for every 1 mole of heptane burned, we produce 7 moles of carbon dioxide. Now we need to convert the volume of gasoline (1000ml) into moles using the density of heptane, which is given as 0.684g/ml. The molar mass of heptane is approximately 100.21 g/mol.
First, we calculate the mass of heptane:
Mass of heptane = Volume of heptane x Density of heptane
= 1000 ml x 0.684 g/ml
= 684 g
Next, we calculate the number of moles of heptane:
Number of moles of heptane = Mass of heptane / Molar mass of heptane
= 684 g / 100.21 g/mol
≈ 6.83 mol
Finally, we calculate the mass of carbon dioxide produced:
Mass of carbon dioxide = Number of moles of heptane x Molar mass of CO2
= 6.83 mol x 44.01 g/mol (molar mass of CO2)
≈ 299.33 g
Therefore, the mass of carbon dioxide produced from the combustion of heptane is approximately 299.33 grams.
b) Using a similar approach, we can calculate the mass of carbon dioxide produced from the combustion of octane (C8H18). The balanced equation is:
C8H18 + 12.5O2 → 8CO2 + 9H2O
From the balanced equation, we can see that for every 1 mole of octane burned, we produce 8 moles of carbon dioxide.
First, we calculate the mass of octane:
Mass of octane = Volume of octane x Density of octane
= 1000 ml x 0.703 g/ml
= 703 g
Next, we calculate the number of moles of octane:
Number of moles of octane = Mass of octane / Molar mass of octane
= 703 g / 114.22 g/mol
≈ 6.15 mol
Finally, we calculate the mass of carbon dioxide produced:
Mass of carbon dioxide = Number of moles of octane x Molar mass of CO2
= 6.15 mol x 44.01 g/mol (molar mass of CO2)
≈ 270.81 g
Therefore, the mass of carbon dioxide produced from the combustion of octane is approximately 270.81 grams.