To make an international telephone call , you need the code for the country you are calling . The codes for country A,B and C are three consecutive integers whose sum is 105. Find the code for each country .

n+n+1 + n+2=105

3n=102
n=34 what is the next, and the next

Let's solve the problem step by step:

Step 1: Define the unknowns
Let's assume the code for the first country is x.
Then the code for the second country will be x + 1 (as they are consecutive integers).
And the code for the third country will be x + 2.

Step 2: Set up the equation
The sum of the three consecutive integers is 105.
So we can write the equation as:
x + (x + 1) + (x + 2) = 105

Step 3: Solve the equation
Simplifying the equation:
3x + 3 = 105
Subtracting 3 from both sides:
3x = 102
Dividing both sides by 3:
x = 34

Step 4: Find the codes for each country
The code for the first country (x) is 34.
The code for the second country (x + 1) is 34 + 1 = 35.
The code for the third country (x + 2) is 34 + 2 = 36.

So, the code for country A is 34, for country B is 35, and for country C is 36.

To find the codes for countries A, B, and C, we need to find three consecutive integers whose sum is 105.

Let's assume the code for country A is x. Since the codes for A, B, and C are three consecutive integers, the code for country B would be x + 1, and the code for country C would be x + 2.

The sum of these three consecutive integers is given by:
x + (x + 1) + (x + 2) = 105

Simplifying the equation, we have:
3x + 3 = 105

Subtracting 3 from both sides, we get:
3x = 102

Dividing both sides by 3, we find:
x = 34

Now, we can find the codes for countries A, B, and C:
Country A: x = 34
Country B: x + 1 = 34 + 1 = 35
Country C: x + 2 = 34 + 2 = 36

Therefore, the code for country A is 34, the code for country B is 35, and the code for country C is 36.