Find limit as x approaches 5 (x^2-3x-10)/(x-5)

using L'Hopital's rule

lim= (2x-3)/1= 7

Have you had L'Hopital's rule yet?

or factor, Lim (x-5)(x+2)/(x-5)=x+2=7

To find the limit as x approaches 5 for the given expression, we can try substituting the value of x into the expression and see if it is defined.

Let's plug in x = 5 into the expression: (x^2 - 3x - 10) / (x - 5)

(5^2 - 3 * 5 - 10) / (5 - 5)

Simplifying further:

(25 - 15 - 10) / 0

Since the denominator is zero, the expression is undefined at x = 5.

Therefore, the limit as x approaches 5 for the expression (x^2 - 3x - 10) / (x - 5) does not exist.