An air gap exists between fluids in a bottle and the cap of the bottle. At a firm producing olive oil, the gap is critical to the shelf life of their product. If the recent information reveals that the average gap is 9.46 mm with a standard deviation of 0.233, calculate the percentage of product above and below the specification limits of 9.5 +/- 0.5 mm.

The police department of a major city has found that the average height of their 1250 officers is 71 inches with 2.3 inches. How many officers are at least 75 inches tall?

First, if you have a question, it is much better to put it in as a separate post in <Post a New Question> rather than attaching it to a previous question, where it is more likely to be overlooked.

Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability of the Z score. Multiply by 1250.

To calculate the percentage of product above and below the specification limits, we need to first determine the z-scores for the upper and lower limits and then use the standard normal distribution table or a calculator to find the corresponding probabilities.

1. Calculate the z-score for the upper limit:
Z_upper = (Upper Limit - Mean) / Standard Deviation
Z_upper = (9.5 - 9.46) / 0.233

2. Calculate the z-score for the lower limit:
Z_lower = (Lower Limit - Mean) / Standard Deviation
Z_lower = (9.46 - 9.5) / 0.233

3. Find the probabilities associated with the z-scores.
You can use a standard normal distribution table or a calculator to find these probabilities. The area to the left of a z-score represents the percentage of values below that z-score.

4. Calculate the percentage of product below the lower limit:
Percentage_below = Probability(Z < Z_lower) * 100

5. Calculate the percentage of product above the upper limit:
Percentage_above = Probability(Z > Z_upper) * 100

By finding the corresponding probabilities for the z-scores, you can determine the percentage of product above and below the specification limits of 9.5 +/- 0.5 mm.

Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability for ± Z score. Multiply by 100.