A 3.5 Liter sample of 5.8 M NaCL solution is diluted to 55 Liter. What is the molarity of the new solution?
new M = 5.8M x (3.5/55) = ?
To find the molarity of the new solution, we need to use the equation:
M1V1 = M2V2
where:
M1 is the initial molarity of the solution
V1 is the initial volume of the solution
M2 is the final molarity of the solution
V2 is the final volume of the solution
In this case, we are given:
M1 = 5.8 M (initial molarity of the solution)
V1 = 3.5 L (initial volume of the solution)
V2 = 55 L (final volume of the solution)
We need to solve for M2 (final molarity of the solution).
Rearranging the equation, we have:
M2 = (M1 * V1) / V2
Plugging in the given values, we get:
M2 = (5.8 M * 3.5 L) / 55 L
Multiplying the molarity and the volume, and then dividing by the final volume, we find:
M2 = 0.36545454545454545 M
Rounding to an appropriate number of decimal places, the molarity of the new solution is approximately 0.365 M.