Solve for the unknown.
1.) √y+√y+7=7
2.) √x+11=√x +1
How about using some parentheses, so it's clear just what you mean?
√y+√(y+7)=7
√y = 7-√(y+7)
y = 49 - 14√(y+7) + y+7
14√(y+7) = 56
√(y+7) = 4
y+7 = 16
y = 9
check: √9 + √16 = 7
√(x+11) = √x + 1
x+11 = x + 2√x + 1
11 = 2√x + 1
2√x = 10
√x = 5
x = 25
check: √36 = √25 + 1
Can u explain what I have to in question two its still doesnt quite make since
1.) To solve for the unknown in the equation √y + √y + 7 = 7, we need to isolate the variable y.
First, let's simplify the equation by combining like terms. Since we have two square roots of y, we can add them together:
√y + √y + 7 = 7
2√y + 7 = 7
Next, subtract 7 from both sides of the equation:
2√y + 7 - 7 = 7 - 7
2√y = 0
Now, divide both sides of the equation by 2:
(2√y) / 2 = 0 / 2
√y = 0
To solve for y, we need to square both sides of the equation:
(√y)^2 = 0^2
y = 0
Therefore, the value of y that satisfies the equation √y + √y + 7 = 7 is y = 0.
2.) To solve for the unknown in the equation √x + 11 = √x + 1, we need to isolate the variable x.
First, let's simplify the equation by subtracting √x from both sides:
√x - √x + 11 = √x - √x + 1
11 = 1
However, we can see that this statement is not true. This means that the equation has no solution. In other words, there is no value of x that satisfies the equation √x + 11 = √x + 1.