copper is a product of the reaction that occurs when dry ammonia is passed over a sample f heated copper(2) oxide.The equation for the reaction is given: 2NH3+3CuO=3Cu+3H2O+N2
Calculate the mass of copper produced if 0.12dm^3 of nitrogen is produced at room temperature and pressure(rtp)
(relative atomic mass of Cu=64; one mole of gas occupies 24dm^3 at rtp)
0.12 dm^3 x (1 mol/24 dm^3) = ? mols N2
mols Cu = ? mols N2 x (3 mols Cu/1 mol N2) = ?
Then g Cu = mols Cu x atomic mass Cu = ?
Red
To calculate the mass of copper produced in the given reaction, we need to use stoichiometry and the molar ratios provided in the balanced equation.
Let's break down the information given:
1) 2NH3 + 3CuO = 3Cu + 3H2O + N2
The balanced equation shows that 2 moles of ammonia (NH3) react with 3 moles of copper(II) oxide (CuO) to produce 3 moles of copper (Cu) and 1 mole of nitrogen gas (N2).
2) Volume of Nitrogen produced: 0.12 dm^3
We know that 1 mole of gas occupies 24 dm^3 at room temperature and pressure (rtp). Therefore, we can calculate the number of moles of nitrogen produce using the ideal gas law:
Number of moles of nitrogen (N2) = Volume of nitrogen (dm^3) / Molar volume (dm^3/mol)
Number of moles of nitrogen (N2) = 0.12 dm^3 / 24 dm^3/mol
Number of moles of nitrogen (N2) = 0.005 mol
3) Using the stoichiometric ratios:
From the balanced equation, we see that 3 moles of copper (Cu) are produced for every mole of nitrogen (N2) formed.
Therefore, the moles of copper (Cu) produced would be:
Number of moles of copper (Cu) = 3 mol Cu / 1 mol N2
Number of moles of copper (Cu) = 0.005 mol Cu
4) Finding the mass of copper (Cu):
To calculate the mass of copper (Cu), we need to use the molar mass of copper, which is given as 64 g/mol.
Mass of copper (Cu) = Number of moles of copper (Cu) × Molar mass of copper (Cu)
Mass of copper (Cu) = 0.005 mol Cu × 64 g/mol
Mass of copper (Cu) = 0.32 g
Therefore, the mass of copper produced in the reaction is 0.32 g.