if a person inhales 0.1 mol air per breath, and the pressure is 92kpa and body temp is 37 degrees celcius what is the maximum volume of air this person can inhale
Temp = 37 + 273 = 310 K
P V = n R T
V = .1 R (310)/92,000
but R = 8.315 Pascals m^3/mol K
V = .1 * 8.315 * 310 /92,000 meters^3
To calculate the maximum volume of air a person can inhale, we need to use the ideal gas law, which states:
PV = nRT
Where:
P = pressure (in Pascals)
V = volume (in cubic meters)
n = number of moles of gas
R = ideal gas constant (8.314 J/(mol·K))
T = temperature (in Kelvin)
First, let's convert the given pressure from kilopascals to Pascals:
92 kPa = 92,000 Pa
Next, we need to convert the given temperature from Celsius to Kelvin. The Kelvin scale is obtained by adding 273.15 to the Celsius value:
37 °C + 273.15 = 310.15 K
Now, we need to rearrange the ideal gas law to solve for volume (V):
V = nRT / P
Substituting the given values:
V = (0.1 mol) × (8.314 J/(mol·K)) × (310.15 K) / 92,000 Pa
Calculating this expression will give us the maximum volume of air that can be inhaled by the person.