100 mL of LiNO3, 0.241 M is mixed with 240 mL of 0.618 M Ca(NO3)2. What is the final concentration of NO3- in the solution?

To find the final concentration of NO3- in the solution, we need to calculate the moles of NO3- from each individual salt and then divide by the total volume of the solution.

Step 1: Calculate moles of LiNO3:
Moles of LiNO3 = concentration (M) x volume (L)
Moles of LiNO3 = 0.241 M x 0.100 L = 0.0241 moles

Step 2: Calculate moles of Ca(NO3)2:
Moles of Ca(NO3)2 = concentration (M) x volume (L)
Moles of Ca(NO3)2 = 0.618 M x 0.240 L = 0.1483 moles

Step 3: Calculate moles of NO3- ions:
Since both LiNO3 and Ca(NO3)2 dissociate completely in water, each mole of these compounds will provide one mole of NO3- ions.

Total moles of NO3- = moles of LiNO3 + moles of Ca(NO3)2
Total moles of NO3- = 0.0241 moles + 0.1483 moles = 0.1724 moles

Step 4: Calculate the final concentration of NO3-:
Final concentration of NO3- = total moles of NO3- / total volume of solution (in liters)
Final concentration of NO3- = 0.1724 moles / (0.100 L + 0.240 L) = 0.417 M

Therefore, the final concentration of NO3- in the solution is 0.417 M.

To find the final concentration of NO3- in the solution, we need to calculate the total moles of NO3- from both LiNO3 and Ca(NO3)2 and then divide it by the total volume of the solution.

First, let's calculate the moles of NO3- from LiNO3:
Moles of LiNO3 = Volume (in liters) × Molarity
Volume of LiNO3 = 100 mL = 100/1000 = 0.1 L
Molarity of LiNO3 = 0.241 M
Moles of LiNO3 = 0.1 L × 0.241 mol/L = 0.0241 mol NO3-

Now, let's calculate the moles of NO3- from Ca(NO3)2:
Moles of Ca(NO3)2 = Volume (in liters) × Molarity
Volume of Ca(NO3)2 = 240 mL = 240/1000 = 0.24 L
Molarity of Ca(NO3)2 = 0.618 M
Moles of Ca(NO3)2 = 0.24 L × 0.618 mol/L = 0.14832 mol NO3-

Next, we add the moles of NO3- from both compounds:
Total moles of NO3- = Moles of LiNO3 + Moles of Ca(NO3)2 = 0.0241 mol + 0.14832 mol = 0.17242 mol

Finally, we divide the total moles of NO3- by the total volume of the solution:
Total volume of the solution = Volume of LiNO3 + Volume of Ca(NO3)2 = 0.1 L + 0.24 L = 0.34 L

Final concentration of NO3- = Total moles of NO3- / Total volume of the solution
Final concentration of NO3- = 0.17242 mol / 0.34 L

To obtain the final concentration of NO3- in the solution, you can divide 0.17242 mol by 0.34 L and round it to an appropriate number of significant figures.