How many grams of oxygen gas must react to give 2.80g of ZnO?
To determine the amount of oxygen gas required to produce 2.80g of ZnO, we need to calculate the molar ratio between ZnO and oxygen gas using the balanced chemical equation.
The balanced chemical equation for the reaction between zinc (Zn) and oxygen (O₂) to form zinc oxide (ZnO) is:
2 Zn + O₂ → 2 ZnO
From the equation, we can see that 1 mole of oxygen gas reacts with 2 moles of zinc to produce 2 moles of zinc oxide. We can use the molar masses to convert these moles to grams.
The molar mass of ZnO is 81.38 g/mol, while that of O₂ is 32.00 g/mol.
First, calculate the number of moles of ZnO produced:
moles of ZnO = mass of ZnO / molar mass of ZnO
moles of ZnO = 2.80g / 81.38 g/mol
moles of ZnO ≈ 0.034 moles
Since the molar ratio between ZnO and oxygen gas is 1:1, the number of moles of oxygen gas required is also 0.034 moles.
Lastly, calculate the mass of oxygen gas needed:
mass of O₂ = moles of O₂ × molar mass of O₂
mass of O₂ = 0.034 moles × 32.00 g/mol
mass of O₂ ≈ 1.088g
Therefore, approximately 1.088 grams of oxygen gas should react to produce 2.80 grams of ZnO.
To find the number of grams of oxygen gas that must react to give 2.80g of ZnO, we need to use the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between oxygen gas (O2) and zinc (Zn) to form zinc oxide (ZnO) is:
2 Zn + O2 --> 2 ZnO
From the equation, we can see that 1 mole of O2 reacts with 2 moles of ZnO. To find the number of moles of ZnO in 2.80g, we can use the molar mass of ZnO.
The molar mass of ZnO can be calculated by summing the atomic masses of zinc (Zn) and oxygen (O) in the compound:
Molar mass of ZnO = Atomic mass of Zn + Atomic mass of O
= (65.38 g/mol) + (16.00 g/mol)
= 81.38 g/mol
Now, we can calculate the number of moles of ZnO in 2.80g:
Number of moles = Mass / Molar mass
= 2.80 g / 81.38 g/mol
= 0.034 mol
Since the balanced equation shows that 2 moles of ZnO react with 1 mole of O2, we can use this ratio to find the number of moles of O2 that react:
Number of moles of O2 = (Number of moles of ZnO) / 2
= 0.034 mol / 2
= 0.017 mol
Finally, we can convert the number of moles of O2 to grams using the molar mass of O2:
Mass = Number of moles * Molar mass
= 0.017 mol * (32.00 g/mol)
= 0.54 g
Therefore, 0.54 grams of oxygen gas must react to give 2.80 grams of ZnO.
2Zn + O2 ---> 2 ZnO
Zn = 65
O = 16
ZnO = 81 g/mol
2.8 g / 81 g/mol = .0346 mol ZnO
half as many O2 mols = .0173 mol O2
.0173 * 32 g/mol = .553 mol O2