a high school has a student reduction and lost 1/10 of its students. If 198 of its students were left after the reduction. How many students were there to start with.
9/10x = 198
x = 198/(9/10)
x = 220
City High School had a student reduction and lost one thirteenth
of its students. If 264 of its students were left after the reduction, how many students were there originally?
To find the number of students the high school had to start with, we can set up an equation using the information given.
Let's say the number of students at the beginning is represented by "x."
According to the problem, the high school lost 1/10 of its students, which means 1/10 of x were subtracted. This can be written as:
x - (1/10)x = 198
To solve this equation, we'll first simplify it:
(9/10)x = 198
Next, we can isolate x by multiplying both sides of the equation by the reciprocal of 9/10, which is 10/9:
x = 198 * (10/9)
Calculating this:
x = 220
Therefore, the high school originally had 220 students.
To solve this problem, we can use a proportion. Let's assume the initial number of students in the high school is represented by "x".
We know that after the reduction, only 1/10th of the students were left, which means the high school has 9/10th of the initial number of students.
So we can set up the proportion:
(9/10) * x = 198
To solve for x, we can cross multiply:
9 * x = 10 * 198
Now, we can solve for x:
9x = 1980
Dividing both sides of the equation by 9:
x = 220
Therefore, there were 220 students in the high school to start with.