3NO2 + H2O -> 2HNO3 + NO
Calculate the percent yield for the following reaction if 76.8 g of H2O reacted and 125 g of NO were produced.
To calculate the percent yield, we need to determine the theoretical yield and actual yield, and then use the formula:
Percent Yield = (Actual Yield / Theoretical Yield) × 100%
First, let's find the theoretical yield of the product, HNO3:
From the balanced equation, we see that the stoichiometric ratio between H2O and HNO3 is 1:2. This means that for every 1 mole of H2O, we should get 2 moles of HNO3.
1 mole of H2O is approximately 18 g (molar mass of H2O), so 76.8 g of H2O is (76.8 / 18) moles.
Now, let's calculate the theoretical yield of HNO3:
Theoretical Yield = 2 × (76.8 / 18) moles
Next, we can convert the moles of HNO3 to grams:
The molar mass of HNO3 is approximately 63 g/mol. Thus,
Theoretical Yield = 2 × (76.8 / 18) × 63 g
Now we can substitute the values into the equation for percent yield:
Percent Yield = (Actual Yield / Theoretical Yield) × 100%
= (125 g / [2 × (76.8 / 18) × 63 g]) × 100%
Calculating this value will give us the percent yield of the reaction.
To calculate the percent yield for a chemical reaction, you need to know both the actual yield (the amount of product obtained) and the theoretical yield (the maximum amount of product that could be obtained).
In this case, the actual yield is given as 125 g of NO. The theoretical yield can be calculated by stoichiometry, using the balanced chemical equation:
3NO2 + H2O -> 2HNO3 + NO
Looking at the coefficients of the balanced equation, we see that the amount of NO produced is directly proportional to the amount of H2O. So, we can set up a proportion:
(125 g NO) / (x g H2O) = (2 mol HNO3) / (76.8 g H2O)
To find x, we can cross-multiply and solve for x:
(125 g NO) * (76.8 g H2O) = (2 mol HNO3) * (x g H2O)
x = (125 g NO) * (76.8 g H2O) / (2 mol HNO3)
Now we can calculate the theoretical yield of H2O:
x = (125 g NO) * (76.8 g H2O) / (2 mol HNO3)
x ≈ 3201.6 g H2O
The theoretical yield of H2O is approximately 3201.6 g.
Finally, we can calculate the percent yield using the formula:
Percent Yield = (Actual Yield / Theoretical Yield) * 100%
Percent Yield = (125 g NO / 3201.6 g H2O) * 100%
Percent Yield ≈ 3.9%
Therefore, the percent yield for the reaction is approximately 3.9%.
25%
mols H2O = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2O to mols NO.
Convert mols NO to g. g NO = mols NO x molar mass NO. This is the theoretical yield (TY). The actual yield (AY) is 125g.
% yield = (AY/TY)*100 = ?