How do I balance
CuSO4 + NH3 + H2O = (NH4)2SO4 + Cu(NH3)4(OH)2
Thank you!!!
Check this to confirm.
CuSO4 + 6NH3 + 2H2O = (NH4)2SO4 + Cu(NH3)4(OH)2
To balance the chemical equation CuSO4 + NH3 + H2O = (NH4)2SO4 + Cu(NH3)4(OH)2, we need to ensure that the number of each type of atom is the same on both sides of the equation. Here's how you can balance it step by step:
1. Start by balancing the atoms that appear in only one compound on each side of the equation. In this case, we have Cu, S, N, H, and O.
2. Balance the copper (Cu) atoms: There is 1 Cu atom on the left side and 1 on the right side, so the Cu atoms are already balanced.
3. Balance the sulfur (S) atoms: There is 1 S atom on the left side and 1 on the right side, so the S atoms are already balanced.
4. Balance the nitrogen (N) atoms: There are 4 N atoms on the right side, coming from the (NH4)2SO4 and Cu(NH3)4(OH)2 compounds. To balance this, we need 4 N atoms on the left side. We can do this by placing a coefficient of 4 in front of NH3 on the left side.
Now the equation becomes:
CuSO4 + 4NH3 + H2O = (NH4)2SO4 + Cu(NH3)4(OH)2
5. Balance the hydrogen (H) atoms: There are 12 H atoms on the right side, coming from the (NH4)2SO4 and Cu(NH3)4(OH)2 compounds. To balance this, we need 12 H atoms on the left side. We can do this by placing a coefficient of 6 in front of H2O on the left side.
The balanced equation becomes:
CuSO4 + 4NH3 + 6H2O = (NH4)2SO4 + Cu(NH3)4(OH)2
6. Balance the oxygen (O) atoms: There are 10 O atoms on the right side, coming from the (NH4)2SO4 and Cu(NH3)4(OH)2 compounds. To balance this, we need 12 O atoms on the left side. We can do this by placing a coefficient of 6 in front of CuSO4 on the left side.
The final balanced equation is:
6CuSO4 + 4NH3 + 6H2O = (NH4)2SO4 + Cu(NH3)4(OH)2
Remember, when balancing equations, it is important to adjust only the coefficients, not the subscripts within the chemical formulas, as it would change the compounds themselves.