In 250 mL of a 0.35 M solution of NaOH, there are how many grams of NaOH?
mols = M x L = ?
Then mols x molar mass = grams.
To find the number of grams of NaOH in a solution, you can use the equation:
grams = moles × molar mass.
First, calculate the number of moles of NaOH in the solution.
moles = concentration × volume (L).
Given:
Concentration (C) = 0.35 M
Volume (V) = 250 mL = 0.25 L
moles = 0.35 M × 0.25 L
= 0.0875 moles
Next, find the molar mass of NaOH.
Molar mass of NaOH = atomic mass of Na + atomic mass of O + atomic mass of H
= 22.99 g/mol + 15.999 g/mol + 1.008 g/mol
= 39.997 g/mol (approximately 40 g/mol)
Finally, calculate the grams of NaOH.
grams = 0.0875 moles × 40 g/mol
= 3.5 grams
Therefore, there are approximately 3.5 grams of NaOH in 250 mL of a 0.35 M solution.
To find the number of grams of NaOH in a solution, we can use the formula:
Mass (grams) = Molarity (mol/L) x Volume (L) x Molecular Weight (g/mol)
In this case, we are given:
Molarity = 0.35 M
Volume = 250 mL = 0.25 L
Molecular Weight of NaOH = 22.99 g/mol (Na) + 16 g/mol (O) + 1.01 g/mol (H) = 39.99 g/mol
Plugging these values into the formula, we get:
Mass (grams) = 0.35 M x 0.25 L x 39.99 g/mol
Calculating this, we find:
Mass (grams) = 3.49725 grams
Therefore, there are approximately 3.5 grams of NaOH in 250 mL of a 0.35 M solution.