Jane had $7 and her sister had $2. Their parents gave each of them an equal amount of money. Then, Jane had twice as much money as her sister. How much money did their parents give each of them
Try trial and error. What do you find?
7 + x
2 + x
7+x = 2 (2+x)
7 + x = 4 + 2 x
x = 3
This still makes noooooooo sense, please, some one help!
To find out how much money their parents gave each of them, we need to understand the information given in the question and then solve the problem step by step.
1. According to the question, Jane initially had $7 and her sister had $2.
2. Their parents then gave each of them an equal amount of money.
3. After receiving the additional money, Jane had twice as much money as her sister.
To solve this problem, we can use algebraic variables to represent the unknown quantities. Let's assume that the amount of money given to each child by their parents is represented by the variable "x".
Based on the given information, we can set up the following equations:
Jane's final amount of money: $7 + x
Sister's final amount of money: $2 + x
According to the problem, Jane had twice as much money as her sister, so we can write the equation:
7 + x = 2(2 + x)
Now, let's solve for "x" to find out how much money their parents gave each of them:
7 + x = 4 + 2x (distributing the 2)
x - 2x = 4 - 7 (subtracting x from both sides and simplifying)
-x = -3 (simplifying the equation)
x = 3 (dividing both sides by -1)
Therefore, their parents gave each child $3.