A 250kg box is pushed horizontally with a force of 750 Newtons. If the coefficient of friction is 0.25, calculate the net acceleration of the crate.
I am confused how I am to find the net acceleration. I solved to find FN and FG is 2452 N is that correct
Yes, but multiply that by .25 to get the friction force
750 - 250 * 9.8 * .25 = 250 a
750 - 612 = 250 a
To find the net acceleration of the crate, we need to consider the forces acting on it. In this case, the main forces are the applied force (750 Newtons) pushing the crate horizontally and the force of friction acting in the opposite direction.
The force of friction can be calculated using the equation:
Frictional force (Ff) = coefficient of friction (µ) * normal force (FN)
To calculate the normal force (FN), we need to consider the weight of the crate. The weight of an object can be calculated using the equation:
Weight (W) = mass (m) * acceleration due to gravity (g)
Given that the mass of the crate is 250 kg and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the weight as follows:
W = 250 kg * 9.8 m/s² = 2450 N
Therefore, the normal force (FN) is equal to the weight of the crate, which is 2450 N.
Now, substituting the values into the equation for frictional force:
Ff = 0.25 * 2450 N = 612.5 N
Since the frictional force acts in the opposite direction to the applied force, we can say that:
Net force (Fnet) = Applied force - Frictional force
Fnet = 750 N - 612.5 N = 137.5 N
Finally, we can calculate the net acceleration (a) using Newton's second law of motion:
Fnet = mass * acceleration
137.5 N = 250 kg * a
Rearranging the equation to solve for acceleration:
a = 137.5 N / 250 kg ≈ 0.55 m/s²
Therefore, the net acceleration of the crate is approximately 0.55 m/s².