a car traveling 8 m/s suddenly brakes to a complete stop. THe stopping time was .36 seconds. what is the acceleration of the car?
let the acceleration be a , (I expect a to be negative)
v = at + c
when t = 0 , v = 8
8 = 0+c ---> c = 0
so v = at + 8
when t = .36, v = 0
0 = a(.36) + 8
a = -8/.36 = appr -22.2 m/s^2
To find the acceleration of the car, we can use the equation:
acceleration = (final velocity - initial velocity) / time
Given:
- Initial velocity (u) = 8 m/s (The car's speed before braking)
- Final velocity (v) = 0 m/s (The car's speed after coming to a stop)
- Time (t) = 0.36 seconds (The stopping time)
Using the formula, we can plug in the values:
acceleration = (0 - 8) / 0.36
Now let's calculate:
acceleration = -8 / 0.36
This gives us:
acceleration ≈ -22.22 m/s^2
The negative sign indicates that the car is decelerating or slowing down.