The speeds of two trains A and B are in the ratio of 5:6. A takes 36 minutes more than B to reach the destination.what is the time taken by A to reach the destination to cover the same distance?
B: X min.
A: (X+36) min.
A/B = (x+36)/x = 6/5
5x + 180 = 6x
5x - 6x = -180
-X = -180
X = 180 min.
X+36 = 180+36 = 216 min.
The speeds of two trains A and B are in the ratio of 5:6. A takes 30 minutes more than B to reach the destination.what is the time taken by A to reach the destination to cover the same distance?
To solve this problem, we will use the concept of relative speeds of two objects moving in the same direction.
Let's assume the speed of train A is 5x units (where x is a constant) and the speed of train B is 6x units.
Now, we know that time is inversely proportional to speed when the distance traveled is constant. In other words, if the speed of an object is greater, it will take less time to cover the same distance.
So, train A is slower than train B because its speed is 5x units compared to train B's 6x units.
Now, we are given that train A takes 36 minutes more than train B to reach the destination.
Let's assume the time taken by train B to cover the distance is t minutes.
Therefore, the time taken by train A to cover the same distance would be (t + 36) minutes.
Since time is equal to distance divided by speed, we can set up the following equation:
Distance/Speed of A = (t + 36) minutes
Distance/Speed of B = t minutes
Now, as the distance covered by both the trains is the same, we can equate the two expressions:
Distance/Speed of A = Distance/Speed of B
Dividing distance from both sides gives:
1/Speed of A = 1/Speed of B
Substituting the values for the speeds of train A and train B:
1/5x = 1/6x
To solve this equation, we can cross-multiply:
6x = 5x
Simplifying,
x = 0
It means the speed of the trains is 0, which doesn't make sense. Therefore, there is no real solution to this problem.
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