A ball is thrown horizontally with a velocity of 40 m/s from the top of a building. Find its velocity and displacement after 3 s.
u = 40 forever
so
x = 40 t
Vi = 0
v down = 0 + 9.8 t
= 9.8 t
z = height at top - 4.9 t^2
so
x = 40 t
Vi = 0
v down = 0 + 9.8 t
= 9.8 t
z = height at top - 4.9 t^2