Using your results from the titration what mass of antacid is required to neutralized 25 ml of HCl.
RESULTS: titration: mass of antacid:V of Hcl neutralized :
1:0.31.25.60
2:0.295.32.20
3:0.300.33.20
I responded earlier that I couldn't make sense of this because of the spacing (or lack thereof). You haven't helped at all because you haven't changed the spacing. I have used ...... as spacers OR you can write on separate lines but you can't make the page recognize more than 1 space at a time.
I found your other post and saw your non-response BUT you told me what the numbers stood for. Find that post, give me the concns of the HCl and stomach acid, and I can verify your work.
To find the mass of antacid required to neutralize 25 ml of HCl, we can use the information provided in the results of the titration.
First, let's analyze the data given in the results:
Titration 1:
- Mass of antacid: 0.31 g
- Volume of HCl neutralized: 1.25 ml
Titration 2:
- Mass of antacid: 0.295 g
- Volume of HCl neutralized: 2.20 ml
Titration 3:
- Mass of antacid: 0.30 g
- Volume of HCl neutralized: 3.20 ml
To determine the mass of antacid required to neutralize 25 ml of HCl, we need to establish a relationship between the mass of antacid and the volume of HCl neutralized.
From the given data, we can see that the mass of antacid is directly proportional to the volume of HCl neutralized. To find the proportionality constant, we can divide the mass of antacid by the volume of HCl neutralized for each titration:
Titration 1: 0.31 g / 1.25 ml = 0.248 g/ml
Titration 2: 0.295 g / 2.20 ml = 0.134 g/ml
Titration 3: 0.30 g / 3.20 ml = 0.094 g/ml
Now, we can calculate the average proportionality constant:
(0.248 g/ml + 0.134 g/ml + 0.094 g/ml) / 3 = 0.15867 g/ml
Finally, we can use the average proportionality constant to calculate the mass of antacid required to neutralize 25 ml of HCl:
Mass of antacid = Proportionality constant * Volume of HCl neutralized
Mass of antacid = 0.15867 g/ml * 25 ml = 3.96675 g
Therefore, approximately 3.97 grams of antacid is required to neutralize 25 ml of HCl based on the given data from the titration.