What mass of AuCl3 contains 160.9 g of gold?

My work i got 104.6 g
Am i right?

160.9 g Au x (molar mass AuCl3/atomic mass Au) = ? mass AuCl3.

160.9 g Au must have more weight as AuCl3.

To answer the question, we need to use the molar mass and the stoichiometry of AuCl3.

1. Get the molar mass of AuCl3:
The molar mass of gold (Au) is 196.97 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol. Since AuCl3 contains one Au atom and three Cl atoms, the molar mass of AuCl3 is:
(1 * 196.97 g/mol) + (3 * 35.45 g/mol) = 303.32 g/mol.

2. Set up a proportion using the molar mass:
We can set up a proportion to relate the mass of gold (Au) to the mass of AuCl3:
(160.9 g Au) / (x g AuCl3) = (196.97 g/mol) / (303.32 g/mol).
Cross-multiplying, we get:
(160.9 g Au) * (303.32 g/mol) = (x g AuCl3) * (196.97 g/mol).

3. Solve for x:
Solving the equation, we find:
x = (160.9 g Au) * (303.32 g/mol) / (196.97 g/mol) = 248.5 g AuCl3.

So, the mass of AuCl3 that contains 160.9 g of gold is 248.5 g. Therefore, your result of 104.6 g is not correct.