physics

a concrete slab of mass 400 kg accelerates down a concrete slope inclined at 35 degrees. the coefficient of kinetic friction between the slab and slope is 0.60. determine the acceleration of the block

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asked by ezana
  1. normal force = 400 g cos 35
    friction force up slope = .6 (400 g) cos 35

    weight component down slope = 400 g sin 35

    400 a = 400 g sin 35 - .6 (400 g cos 35)

    a = g (sin 35 - .6 cos 35) = .082 g

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    posted by Damon
  2. Home werk

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    posted by sied
  3. the momentum after the collision

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  4. Lagaga

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    posted by Bgagag
  5. 400kg

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    posted by Bgagag

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