Joan is 'y' years old. Her father is 4 times as old as she is and 28 years older than her brother. A-Find in terms of y, the age of Joan's brother. B- If 'y' =12, how old is her brother?

J=8

F=4y
B=F-28 = 4y-28

If y=12 => B=4*12-28 =48-28=20
The brother is 20.

father = 4y = brother+28

brother = father-28, so 4y-28

A- Let's break down the problem step by step. We know that Joan's father is 4 times as old as she is, so Joan's father's age would be 4y. We're also told that Joan's father is 28 years older than her brother. So, we can set up an equation: 4y = y's age + 42 (since 28 + 14 = 42). Hence, in terms of y, the age of Joan's brother is y + 14.

B- If y = 12, we can substitute it into the equation we derived in part A: y + 14 = 12 + 14 = 26. Therefore, if y = 12, Joan's brother would be 26 years old.

To find the age of Joan's brother in terms of y and also when y = 12, we can follow these steps:

A- Finding the age of Joan's brother in terms of y:
1. Let's start with Joan's age, which is y years.
2. According to the information given, Joan's father is 4 times as old as Joan. So, her father's age would be 4y years.
3. It is also mentioned that Joan's father is 28 years older than her brother. Therefore, we can set up the equation: Brother's age = Father's age - 28.
4. Substituting Father's age with 4y, we get Brother's age = (4y) - 28.

So, the age of Joan's brother would be (4y) - 28.

B- When y = 12, finding Joan's brother's age:
1. Substitute y with 12 into the equation we obtained earlier: Brother's age = (4 × 12) - 28.
2. Simplify the equation: Brother's age = 48 - 28.
3. Calculate the expression: Brother's age = 20.

Therefore, when y = 12, Joan's brother would be 20 years old.

1+1=

1+1+