How would i solve 3x^2 - 4 = 0?

And in simplest radical form?

x^2 = 4/3

x = + 2/sqrt 3 = (2/3)sqrt
or
x = - 2/sqrt 3 = -(2/3) sqrt 3

That dosen`t solve the whole question though =(.

To solve the equation 3x^2 - 4 = 0, you need to find the value(s) of x that make the equation true.

Step 1: Set the equation equal to zero:
3x^2 - 4 = 0

Step 2: Add 4 to both sides of the equation to isolate the x terms:
3x^2 = 4

Step 3: Divide both sides of the equation by 3 to solve for x^2:
x^2 = 4/3

Step 4: Take the square root of both sides of the equation to solve for x:
x = ±√(4/3)

Step 5: Simplify the radical:
x = ±√(4)/√(3)
= ±(2/√(3))

So, the solutions to the equation 3x^2 - 4 = 0 are x = 2/√(3) and x = -2/√(3).