what is the partial pressure of hydrogen in a flask containing 2g hydrogen and 32g sulphur dioxide
The total pressure is equal to sum of partial vapour pressures then how u use this formula ??
To calculate the partial pressure of hydrogen in the flask, we need to use the concept of the mole fraction of the gas.
Step 1: Determine the moles of hydrogen and sulphur dioxide.
- Moles of hydrogen (H₂) = mass of hydrogen (2 g) / molar mass of hydrogen (2 g/mol) = 1 mole
- Moles of sulphur dioxide (SO₂) = mass of sulphur dioxide (32 g) / molar mass of sulphur dioxide (64 g/mol) = 0.5 moles
Step 2: Calculate the total moles of gas in the flask.
- Total moles of gas = moles of hydrogen + moles of sulphur dioxide = 1 + 0.5 = 1.5 moles
Step 3: Calculate the mole fraction of hydrogen.
- Mole fraction of hydrogen = moles of hydrogen / total moles of gas = 1 / 1.5 = 0.67
Step 4: Calculate the total pressure of the gas mixture using Dalton's Law of Partial Pressure.
- In this case, the total pressure is not given, so we need additional information or assumptions about the conditions.
Step 5: Calculate the partial pressure of hydrogen.
- Partial pressure of hydrogen = mole fraction of hydrogen × total pressure
Without additional information or assumptions about the total pressure, we cannot determine the partial pressure of hydrogen in the flask.
Is this at STP? If not what is the volume or total pressure?
mols H2 = grams/molar mass
mols SO2 = grams/molar mass
total mols = mols H2 + mols SO2
XH2 = mols H2/total mols
XSO2 = mols SO2/total mols
pH2 = XH2*Ptotal
XSO2 = XSO2*Ptotal