A 30-caliber rifle with a mass of 3.54 kg fires a 7.33- g bullet with a speed of 596 m/s with respect to the ground. What kinetic energy is released by the explosion of the gunpowder that fires the bullet? (Note there is a tolerance 0.1 percent for the answer)
Well, well, well! Talk about a bang! Let's calculate the kinetic energy that was released when this explosive party started.
First, we need to convert the mass of the bullet to kilograms. There are 1000 grams in a kilogram, so 7.33 grams is equal to 0.00733 kilograms.
Now, let's plug the given values into the kinetic energy equation: KE = 0.5 * mass * velocity^2.
KE = 0.5 * 0.00733 kg * (596 m/s)^2
Now it's just simple arithmetic. Drum roll, please!
KE ≈ 0.5 * 0.00733 kg * 596^2 m^2/s^2
KE ≈ 0.5 * 0.00733 * 354016
KE ≈ 1298.51 Joules
And, voila! The kinetic energy released by the explosion of the gunpowder is approximately 1298.51 Joules.
To find the kinetic energy released by the explosion of the gunpowder, we can use the formula:
Kinetic energy = (1/2) * mass * velocity^2
First, let's convert the mass of the bullet from grams to kilograms:
Mass of bullet = 7.33 g = 7.33 * 10^-3 kg
Now we can substitute the values into the formula:
Kinetic energy = (1/2) * 7.33 * 10^-3 kg * (596 m/s)^2
Simplifying this expression, we get:
Kinetic energy ≈ 0.5 * 7.33 * 10^-3 kg * 596^2 m^2/s^2
Now, calculate the value of the expression:
Kinetic energy ≈ 0.000022 kg * 596^2 m^2/s^2 ≈ 0.000022 * 355216 m^2/s^2 ≈ 7.815536 m^2/s^2
Rounded to the nearest 0.1 percent, the kinetic energy released by the explosion of the gunpowder is 7.82 m^2/s^2.
To calculate the kinetic energy released by the explosion of the gunpowder, we can use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
where:
- Kinetic Energy is the energy released by the explosion,
- mass is the mass of the bullet,
- velocity is the velocity of the bullet.
First, let's convert the mass of the bullet from grams to kilograms:
mass_bullet = 7.33 g = 7.33 * 10^(-3) kg
Now we can substitute the given values into the formula:
Kinetic Energy = (1/2) * 7.33 * 10^(-3) kg * (596 m/s)^2
Calculating this equation gives us the kinetic energy released by the explosion of the gunpowder.